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Question

Two coherent monochromatic light beams of intensities I and 9I are super imposed. The maximum and the minimum intensities of the resultant beam are

A
10I and zero
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B
10I and 8I
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C
10I and 4I
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D
16I and 4I
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Solution

The correct option is D 16I and 4I
The resultant intensity , IR=I1+I2+2I1I2cosδ
where δ be the phase difference between the two waves.
For maximum intensity, δ=0o so IRmax=I+9I+2I(9I)cos0=16I
For minimum intensity, δ=180o so IRmin=I+9I+2I(9I)cos180=4I

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