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Question

Two coherent monochromatic light beams of intensity I and 4I are superimposed. The maximum and minimum possible intensities in the resulting beam are,

A
5I and I
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B
5I and 3I
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C
9I and I
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D
9I and 3I
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Solution

The correct option is C 9I and I
Here, I1=I, I2=4I

The resultant intensity at a point due to superposition of waves is given by,

IR=I1+I2+2I1I2 cosϕ

For maxima, cosϕ=1, so that,
Imax=I1+I2+2I1I2
=I+4I+2I×4I
Imax=9I

Similarly, for minima, cosϕ=1

And, Imax=I1+I22I1I2

=I+4I2I×4I
Imin=I

Hence, (C) is the correct answer.

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