Two coherent sources with intensity ratio - produce interference- The fringe visibility will be

The correct option is B 2√(β)/1+β Fringe visibility is defined as: Visibility = 2√(I_1I_2)I_1 + I_2 Given, I_1I_2 = β ∴ visibility = 2 I_2 ...

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Standard XII

Physics

Maxima & Minima in YDSE

Two coherent ...

Question

Two coherent sources with intensity ratio $β$ produce interference. The fringe visibility will be

\frac{2 \sqrt{β}}{1 + β}

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2 β

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\frac{2}{1 + β}

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\frac{β}{1 + β}

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Solution

The correct option is B $\frac{2 \sqrt{β}}{1 + β}$
Fringe visibility is defined as: $V i s i b i l i t y = \frac{2 \sqrt{I_{1} I_{2}}}{I_{1} + I_{2}}$
Given, $\frac{I_{1}}{I_{2}} = β$
$∴ v i s i b i l i t y = \frac{2 I_{2} \sqrt{β}}{I_{2} (1 + β)} = \frac{2 \sqrt{β}}{1 + β}$

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Two coherent sources with intensity ratio β produce interference. The fringe visibility will be

The correct option is B 2√β1+βFringe visibility is defined as: Visibility=2√I1I2I1+I2Given, I1I2=β∴visibility=2I2√βI2(1+β)=2√β1+β

Two coherent sources with intensity ratio $β$ produce interference. The fringe visibility will be

The correct option is B $\frac{2 \sqrt{β}}{1 + β}$
Fringe visibility is defined as: $V i s i b i l i t y = \frac{2 \sqrt{I_{1} I_{2}}}{I_{1} + I_{2}}$
Given, $\frac{I_{1}}{I_{2}} = β$
$∴ v i s i b i l i t y = \frac{2 I_{2} \sqrt{β}}{I_{2} (1 + β)} = \frac{2 \sqrt{β}}{1 + β}$