Two coils A and B are connected in series across a 240 V- 50 Hz supply- The resistance of A is 5 - and the inductance of B is 0-02 H- The power consumed is 3 kW and the power factor is 0-75- The impedence of the circuit is

The correct option is C 14.4 Ω Given : #160; E_v = 240 V , #160; cosϕ = 0.75 and p = 3000 W Power consumed #160; P=E_v^2cosϕ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Galvanometer

Two coils A...

Question

Two coils $A$ and $B$ are connected in series across a $240 V, 50 Hz$ supply. The resistance of $A$ is $5 Ω$ and the inductance of $B$ is $0.02 H$ . The power consumed is $3 kW$ and the power factor is $0.75$ . The impedence of the circuit is

0.144 Ω

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.44 Ω

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14.4 Ω

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

144 Ω

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $14.4 Ω$
Given : $E_{v} = 240 V$ , $cos ϕ = 0.75$ and $p = 3000 W$
Power consumed $P = \frac{E_{v}^{2} cos ϕ}{Z} = 3000$
where $Z$ is the impedence of the circuit.
$∴ \frac{(240)^{2} (0.75)}{Z} = 3000$
$\Rightarrow Z = 14.4 Ω$

Suggest Corrections

Similar questions

Q. Two coils A and B are connected in series with an ac source of emf 220 V (rms) and frequency 50 Hz. The resistance of A is 4

Ω

and inductance of B is 0.02 H. The power loss in the circuit is 3 KW and power factor is 0.75. Then, the resistance of coil B is:

A series RLC circuit contains resistance of 10Ω, an inductance of 0.2H and a capacitor of 100uF .. Its powered by a supply of 200V, 50Hz. Calculate the total circuit impedance, the circuits current, power factor and draw the voltage phasor diagram.

Q. A resistor and a capacitor are connected to an A.C. supply of

200 V, 50 H z

in series. The current in the circuit is

2 A

. If the power consumed in the circuit is

100 W

then the capacitive reactance in the circuit is

Q. A circuit has a coil of resistance

50 Ω

and inductance

\frac{3}{π} H

. It is connected in series with a condenser of

\frac{40}{π} μ F

and AC supply of 200 V and 50 cycles/s. Which of the following is/are correct?

Q. A resistor and capacitor is connected to

A C

supply of

200 V

50 H z

an series. The current in circuit is

2 A

. If power consumed in circuit is

100 W

the resistance in

A C

circuit is

Join BYJU'S Learning Program

Two coils A and B are connected in series across a 240 V,50 Hz supply. The resistance of A is 5 Ω and the inductance of B is 0.02 H. The power consumed is 3 kW and the power factor is 0.75. The impedence of the circuit is

The correct option is C 14.4 ΩGiven : Ev=240 V, cosϕ=0.75 and p=3000 WPower consumed P=E2vcosϕZ=3000where Z is the impedence of the circuit.∴(240)2(0.75)Z=3000 ⇒Z=14.4 Ω

Two coils $A$ and $B$ are connected in series across a $240 V, 50 Hz$ supply. The resistance of $A$ is $5 Ω$ and the inductance of $B$ is $0.02 H$ . The power consumed is $3 kW$ and the power factor is $0.75$ . The impedence of the circuit is

The correct option is C $14.4 Ω$
Given : $E_{v} = 240 V$ , $cos ϕ = 0.75$ and $p = 3000 W$
Power consumed $P = \frac{E_{v}^{2} cos ϕ}{Z} = 3000$
where $Z$ is the impedence of the circuit.
$∴ \frac{(240)^{2} (0.75)}{Z} = 3000$
$\Rightarrow Z = 14.4 Ω$