Two coils A and B are separated by a certain distance. If a current of 4 A flows through A, a magnetic flux of $10^{- 3}$ Wb passes through B (no current through B).If no current passes through A and a current of 2 A passes through B, then the flux through A is then

5 \times 10^{- 3}

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4 \times 10^{- 4}

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5 \times 10^{- 4}

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2 \times 10^{- 3}

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Solution

The correct option is C $5 \times 10^{- 4}$
Magnetic flux linked with coil
$ϕ_{B} = M I_{A}$
$∴ M = \frac{ϕ_{B}}{I_{A}} = \frac{10^{- 3}}{4}$ henry
Magnetic flux linked with coil A
$ϕ_{A} = M I_{B} = \frac{10^{- 3}}{4} \times 2 = 5 \times 10^{- 4} W b$

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Two coils A and B are separated by a certain distance. If a current of 4 A flows through A, a magnetic flux of 10−3 Wb passes through B (no current through B).If no current passes through A and a current of 2 A passes through B, then the flux through A is then

The correct option is C 5×10−4Magnetic flux linked with coilϕB=MIA∴M=ϕBIA=10−34henryMagnetic flux linked with coil A ϕA=MIB=10−34×2=5×10−4Wb

Two coils A and B are separated by a certain distance. If a current of 4 A flows through A, a magnetic flux of $10^{- 3}$ Wb passes through B (no current through B).If no current passes through A and a current of 2 A passes through B, then the flux through A is then

The correct option is C $5 \times 10^{- 4}$
Magnetic flux linked with coil
$ϕ_{B} = M I_{A}$
$∴ M = \frac{ϕ_{B}}{I_{A}} = \frac{10^{- 3}}{4}$ henry
Magnetic flux linked with coil A
$ϕ_{A} = M I_{B} = \frac{10^{- 3}}{4} \times 2 = 5 \times 10^{- 4} W b$