wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two coils A and B have inductance 1.0H and 2.0H respectively. The resistance of each coil is 10Ω. Each coil is connected to an ideal battery of emf 2.0V at t=0. Let iA and iB be the currents in the two circuit at time t. Find the ratio iA/iB at (a) t=100ms, (b) t=200ms and (c) t=1s

Open in App
Solution

LA=1.0H;LB=2.0H;R=10Ωt=0.1s,τA=0.1,τB=L/R=0.2
iA=i0(1et/τ)=2101e0.1×101=0.2(1e1)=0.126424111
iB=i0(1et/τ)=2101e0.1×102=0.2(1e1/2)=0.078693
iAiB=0.126424110.78693=1.6
(b) t=200ms=0.2s
iA=i0(1et/τ)=0.2(1e0.2×10/1)=0.2×0.864663716=0.172932943
iB=i0(1et/τ)=0.2(1e0.2×10/2)=0.2×0.632120=0.126424111
iAiB=0.1729329430.126424111=1.36=1.4
(c) t=1s
iA=0.2(1e1×10/1)
iB=0.2(1e1×10/2)=0.2×0.99326=0.19865241
iAiB=0.199990920.19865241=1.0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Self Induction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon