Question

Two coils are at fixed locations. When coil 1 has no current and the current in coil 2 increases at the rate of $15.0A{s}^{-1}$, the emf in coil 1 is $25mV$. When coil 2 has no current and coil 1 has a current of $3.6A$, the flux linkage in coil 2 is

• A. $16mWb$
• B. $10mWb$
• C. $4.00mWb$
• D. $6.00mWb$

Answer 1

The correct option is D $6.00mWb$

$|M|=\frac{e_1}{\left(d{i}_2/dt\right)}=\frac{{\varphi }_2}{i_1}$
$\therefore {\varphi }_2=\frac{e_1{i}_1}{\left(d{i}_2/dt\right)}=\frac{(25.0\times {10}^{-3})\left(3.6\right)}{\left(15\right)}$
$=6\times {10}^{-3}=6mWb$