Two coils have a mutual inductance 0-005 H- The current changes in the first coil according to the equation I - i m sin- t where i m -10 A and -100 - rad s -1- The maximum value of the emf induced in the second coil isA- 2 -B- 4 -C- 5 -D- -

E=μ dI/dt d/dt(I_m sin ω t)=I_m ω cos ω t dI/dtis maximum ⇒ cos ω t=1 ⇒dI/dt=I_m ω e= μ(I_m ω) e =0.005 × 10 × 100 π = 5 π (maximum value of emf) nbsp; ...

261

You visited us 261 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

RMS Value of Current in Sinusoidal AC

Two coils hav...

Question

Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to the equation $I = i_{m} s i n ω t w h e r e i_{m} = 10 A a n d ω = 100 π r a d s^{- 1}$ . The maximum value of the emf induced in the second coil is

$π$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$2 π$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$4 π$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$5 π$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$5 π$

$e = \frac{μ d I}{d t} \frac{d}{d t} (I_{m} s i n ω t) = I_{m} ω c o s ω t$

$\frac{d I}{d t} is maximum$
$\Rightarrow c o s ω t = 1 \Rightarrow \frac{d I}{d t} = I_{m} ω$
$e = μ (I_{m} ω)$
$e = 0.005 \times 10 \times 100 π = 5 π (maximum value of emf)$

Suggest Corrections

Similar questions

Q. Two coils have mutual inductance

0.005 H

. The current changes in the first coil according to equation

I = I_{0} sin ω t

, where

I_{0} = 10 A

and

w = 100 π r a d s^{- 1}

. The maximum value of emf in the second coil is

Q. Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation

I = I_{o}

sin ωt, where

I_{o}

= 10A and ω = 100

Π

radian/sec. The maximum value of e.m.f. in the second coil is

Q. Two coil have a mutual inductance 0.005 H. The current changes in first coil according to equation

I = I_{0} sin ω t

where

I_{0} = 2 A

and

ω = 100 π r a d / sec

, where . The maximum value of induced emf in second coil is:

Q. The mutual inductance of the system of two coils is

5 m H

. The current in the first coil varies according to the equation

I = I_{o} sin w t

where

I_{o} = 10 A

and

W = 100 π r a d / s

. The value of maximum induced emf in the second coil is _______

Join BYJU'S Learning Program

Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to the equation I=im sin ωt where im=10 A and ω=100π rad s−1 . The maximum value of the emf induced in the second coil is

The correct option is D 5π e=μdIdt ddt(Im sin ωt)=Imωcos ωt dIdtis maximum ⇒cosωt=1⇒dIdt=Imω e=μ(Imω) e=0.005×10×100π=5π (maximum value of emf)

Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to the equation $I = i_{m} s i n ω t w h e r e i_{m} = 10 A a n d ω = 100 π r a d s^{- 1}$ . The maximum value of the emf induced in the second coil is

The correct option is D
$5 π$

$e = \frac{μ d I}{d t} \frac{d}{d t} (I_{m} s i n ω t) = I_{m} ω c o s ω t$

$\frac{d I}{d t} is maximum$
$\Rightarrow c o s ω t = 1 \Rightarrow \frac{d I}{d t} = I_{m} ω$
$e = μ (I_{m} ω)$
$e = 0.005 \times 10 \times 100 π = 5 π (maximum value of emf)$