Question

Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation $I=I_{0}sin\omega t$, where $I_0=10Aand\omega =100\pi radian/sec$. The maximum value of e.m.f. in the second coil is

• A. $2\pi$
• B. $5\pi$
• C. $\pi$
• D. $4\pi$

Answer 1

The correct option is B $5\pi$

$e=M\frac{di}{dt}=0.005\times \frac{d}{dt}\left(i_{0}sin\omega t\right)=0.005\times i_0\omega cos\omega t$
$\therefore e_{max}=0.005\times 10\times 100\pi =5\pi$