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Standard XII

Physics

Magnetic Flux and Faraday's Law

Two coils P...

Question

Two coils $P$ and $Q$ are kept near each other. When no current flows through coil $P$ and current increases in coil $Q$ at the rate $10 A / s$ , the e.m.f. in coil $P$ is $15 m V$ . When coil $Q$ carries no current and current of $1.8 A$ flows through coil $P$ , the magnetic flux linked with the coil $Q$ is

1.4 m W b

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2.2 m W b

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2.7 m W b

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2.9 m W b

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Solution

The correct option is C $2.7 m W b$
$M = \frac{E}{d i / d t} = \frac{15}{10}$
Flux= $M i = 1.5 \times 1.8 = 2.7 m W b$

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Two coils P and Q are kept near each other. When no current flows through coil P and current increases in coil Q at the rate 10A/s, the e.m.f. in coil P is 15 mV. When coil Q carries no current and current of 1.8 A flows through coil P, the magnetic flux linked with the coil Q is

The correct option is C 2.7 m WbM=Edi/dt=1510Flux=Mi=1.5×1.8=2.7mWb

The correct option is C $2.7 m W b$
$M = \frac{E}{d i / d t} = \frac{15}{10}$
Flux= $M i = 1.5 \times 1.8 = 2.7 m W b$