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Standard XII

Physics

Inductors in Circuits

Two coils X a...

Question

Two coils X and Y are lying in a circuit. The change in current in X is $2$ ampere and change in magnetic flux in Y is 0.4 Weber. The coefficient of mutual induction between the coils will be :

0.2 H e n r y

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5 H e n r y

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0.8 H e n r y

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0.4 H e n r y

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Solution

The correct option is A $0.2 H e n r y$
flux in y = $ϕ_{y} = M i_{x}$
Therefore ,
$△ ϕ_{y} = △ (M i_{x}) = M △ i_{x}$
$M = \frac{△ ϕ_{y}}{△ (i_{x})} = 0.2 H$

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Two coils X and Y are lying in a circuit. The change in current in X is 2 ampere and change in magnetic flux in Y is 0.4 Weber. The coefficient of mutual induction between the coils will be :

The correct option is A 0.2Henryflux in y = ϕy=Mix Therefore , △ϕy=△(Mix)=M△ixM=△ϕy△(ix)=0.2H

Two coils X and Y are lying in a circuit. The change in current in X is $2$ ampere and change in magnetic flux in Y is 0.4 Weber. The coefficient of mutual induction between the coils will be :

The correct option is A $0.2 H e n r y$
flux in y = $ϕ_{y} = M i_{x}$
Therefore ,
$△ ϕ_{y} = △ (M i_{x}) = M △ i_{x}$
$M = \frac{△ ϕ_{y}}{△ (i_{x})} = 0.2 H$