Two coins are toosed together. What is the probability of getting:
(i) at least one head
(ii) both heads or both tails

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Solution

$∵$ A coins has two faces Head and Tail or H, T
$∴$ Two coins are toosed
$∴$ Number of coins = $2 \times 2 = 4$
which are HH, HT, TH, TT
(i) At least one head, then
Number of outcomes= 3
$∴$ P(E) = $\frac{N u m b e r o f f a v o u r a b l e o u t c o m e}{N u m b e r o f a l l p o s s i b l e o u t c o m e}$
$= \frac{3}{4}$
(ii) When both head or both tails, then Number of outcomes=2
$∴$ P(E)= $\frac{N u m b e r o f f a v o u r a b l e o u t c o m e}{N u m b e r o f a l l p o s s i b l e o u t c o m e}$
$= \frac{2}{4} = \frac{1}{2}$

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