Question

Two coins are tossed 1000 times and the outcomes are recorded as below

$\begin{array}{cccc}\text{Number of heads}& 2& 1& 0\\ \text{Frequency}& 200& 550& 250\end{array}$

Based on this information, the probability for atmost one head is:

• A. $\frac{1}{5}$
• B. $\frac{1}{4}$
• C. $\frac{4}{5}$
• D. $\frac{3}{4}$

Answer 1

The correct option is C $\frac{4}{5}$

The total number of coins tossed, n(S) = 1000
Number of outcomes in which atmost one head, n = 550 + 250 = 800
$\therefore$ Probability for atmost one head = $\frac{n\left(E\right)}{n\left(S\right)}=\frac{800}{1000}=\frac{4}{5}$
Hence, the probability for atmost one head is $\frac{4}{5}$.