Two coins are tossed $1000$ times and the outcomes are recorded as below:
No of heads
$2$
$1$
$0$
Frequency
$200$
$550$
$250$
Based on this information, the probability for at most one head is $\frac{a}{b}$ . Where $(a, b) = 1$ , then

\frac{1}{5}

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\frac{1}{4}

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\frac{4}{5}

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\frac{3}{4}

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Solution

The correct option is D $\frac{4}{5}$
Total number of outcomes $= 1000$
Number of favourable outcomes $= 800$
Probability = $\frac{800}{1000}$ = $\frac{4}{5}$

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Similar questions

Q. Question 28
Two coins are tossed 1000 times and the outcomes are recorded as below

\begin{matrix} N u m b e r o f h e a d s & 2 & 1 & 0 F r e q u e n c y & 200 & 550 & 250 \end{matrix}

Based on this information, the probability for atmost one head is:

A)

\frac{1}{5}

\frac{1}{4}

\frac{4}{5}

\frac{3}{4}

Question 28
Two coins are tossed 1000 times and the outcomes are recorded as below

$\begin{matrix} Number of heads & 2 & 1 & 0 Frequency & 200 & 550 & 250 \end{matrix}$

Based on this information, the probability for atmost one head is:

A) $\frac{1}{5}$
B) $\frac{1}{4}$
C) $\frac{4}{5}$
D) $\frac{3}{4}$

Q. Two coins are tossed 1000 times and the outcomes are recorded as below

\begin{matrix} Number of heads & 2 & 1 & 0 Frequency & 200 & 550 & 250 \end{matrix}

Based on this information, the probability for atmost one head is:

Two coins are tossed 1000 times and the outcomes are recorded as below
$\begin{matrix} Number of heads & 2 & 1 & 0 Frequency & 200 & 550 & 250 \end{matrix}$

Based on this information, the probability for atmost one head is:

A) $\frac{1}{5}$
B) $\frac{1}{4}$
C) $\frac{4}{5}$
D) $\frac{3}{4}$

Q. Fill In The Blanks

Two coins are tossed 1000 times and outcomes are recorded as below:

Numbers of heads: 2 1 0
Frequency: 200 550 250

The probability of getting at most one head is _______.

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Two coins are tossed 1000 times and the outcomes are recorded as below:No of heads210Frequency200550250Based on this information, the probability for at most one head is ab. Where (a,b)=1, then

The correct option is D 45Total number of outcomes =1000Number of favourable outcomes =800Probability = 8001000 = 45

Two coins are tossed $1000$ times and the outcomes are recorded as below:
No of heads
$2$
$1$
$0$
Frequency
$200$
$550$
$250$
Based on this information, the probability for at most one head is $\frac{a}{b}$ . Where $(a, b) = 1$ , then

The correct option is D $\frac{4}{5}$
Total number of outcomes $= 1000$
Number of favourable outcomes $= 800$
Probability = $\frac{800}{1000}$ = $\frac{4}{5}$