Question

Two coins are tossed 1000 times and the outcomes are recorded as shown below:

Number of heads	2	1	0
Frequency	266	540	194

A coin is thrown at random. What is the probability of getting at most one head?
(a) $\frac{403}{500}$

(b) $\frac{27}{50}$

(c) $\frac{367}{500}$

(d) $\frac{97}{500}$

Answer 1

(c)$\frac{367}{500}$

Explanation:
Total number of tosses = 1000
Number of times 2 heads appear = 266
Number of times 1 head appears = 540
Number of times 0 head appears = 194

If at most 1 head appears, then either 1 head appears or no heads appear = 540 + 194 = 734

P(getting at most 1 head) $=\frac{734}{1000}=\frac{367}{500}$