Question

Two coins are tossed $600$ times and we get two heads $138$ times, one head $192$ times and no heads $270$ times. What is the probability of getting no tails

• A. $\frac{192}{600}$
• B. $\frac{462}{600}$
• C. $\frac{138}{600}$
• D. $\frac{408}{600}$

Answer 1

Answer: (C)

$\frac{138}{600}$

Two coins are tossed $600$ times.

Therefore, $n\left(S\right)=600$.

Let $A$ be the event of getting two heads, $n\left(A\right)=138$.

Let $B$ be the event of getting one head, $n\left(B\right)=192$.

Let $C$ be the event of getting no heads, $n\left(C\right)=270$.

We have to find the probability of getting no tails.

Probability of getting no tails is same as probability of getting two heads.

Therefore, the probability of getting no tails is $\frac{138}{600}$.