Question

Two coins are tossed. Find the probability of the events.

(ii) head does not appear.

Answer 1

Given:
Two coins are tossed.
The sample space is {HH, TH, HT, TT}.
∴ n(S) = 4
Now,
B is the event when the head does not appear.
∴ B = {TT}
Or,
n(B) =1
Thus, we have:
P(B) = $\frac{n\left(\mathrm{B}\right)}{n\left(\mathrm{S}\right)}=\frac{1}{4}$