Two coins are tossed once. Find the probability of getting:
(i) $2$ heads
(ii) at least $1$ tail.

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Solution

Two coins are tossed. The sample set $S$ will be ${H H, H T, T H, T T}$
(i) Let $A$ be the event of getting two heads. Then event $A$ will contain the outcome ${H H}$
$P (A) = \frac{n (A)}{n (S)} = \frac{1}{4}$

(ii) Let $B$ be the event of getting at least $1$ tail. Then, $B$ will contain the outcomes ${H T, T H, T T}$
$P (B) = \frac{n (B)}{n (S)} = \frac{3}{4}$

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