Question

Two coins are tossed simultaneously 200 times and we get two heads: 58 times, one head: 83 times: 0 head: 59 times.
When two coins are tossed at random, what is the probability of getting (i) 2 heads, (ii) 1 head, (iii) 0 head?

Answer 1

Total number of trials = 200
Number of times 2 heads are obtained = 58
Number of times one head is obtained = 83
Number of times no head is obtained = 59

(i) Probability of getting 2 heads = $\frac{\mathrm{Number}\mathrm{of}\mathrm{times}2\mathrm{heads}\mathrm{have}\mathrm{been}\mathrm{obtained}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{trials}}$ = $\frac{58}{200}=\frac{29}{100}$


(ii) Probability of getting 1 head = $\frac{\mathrm{Number}\mathrm{of}\mathrm{times}1\mathrm{head}\mathrm{has}\mathrm{been}\mathrm{obtained}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{trials}}$ = $\frac{83}{200}$


(iii) Probability of getting 0 head = $\frac{\mathrm{Number}\mathrm{of}\mathrm{times}\mathrm{head}\mathrm{has}\mathrm{not}\mathrm{been}\mathrm{obtained}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{trials}}$ = $\frac{59}{200}$