Question

Two coins are tossed simultaneously 600 times to get

2 heads: 234 times, 1 head: 206 times, 0 head: 160 times.

If two coins are tossed at random, what is the probability of getting at least one head?

(a) $\frac{103}{300}$

(b) $\frac{39}{100}$

(c) $\frac{11}{15}$

(d) $\frac{4}{15}$

Answer 1

ANSWER:
Number of times two coins are tossed simultaneously = 600
Number of times of getting at least one head = Number of times of getting 1 head + Number of times of getting
2 heads = 206 + 234 = 440
∴ P(Getting at least one head)
= Number of times of getting at least one head/Number of times two coins are tossed simultaneously=$\frac{440}{600}$=$\frac{11}{15}$
Hence, the correct answer is option (c).