Two Coins Are Tossed Simultaneously. Find the Probability of Getting Exactly One Head.

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Solution

Finding the Probability of Getting Exactly One Head:
If two coins are tossed, the sample space is $\{HH, HT, TH, TT\}$
$n (S) = 4$
The event of getting exactly one head, $E = \{H T, T H\}$
$n (E) = 2$
Therefore, the probability of getting exactly one head $= \frac{2}{4} = \frac{1}{2}$

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Two Coins Are Tossed Simultaneously. Find the Probability of Getting Exactly One Head.

Finding the Probability of Getting Exactly One Head:If two coins are tossed, the sample space is HH,HT,TH,TTn(S)=4The event of getting exactly one head, E=HT,THn(E)=2Therefore, the probability of getting exactly one head =24=12

Finding the Probability of Getting Exactly One Head:
If two coins are tossed, the sample space is $\{HH, HT, TH, TT\}$
$n (S) = 4$
The event of getting exactly one head, $E = \{H T, T H\}$
$n (E) = 2$
Therefore, the probability of getting exactly one head $= \frac{2}{4} = \frac{1}{2}$