Question

Two coins are tossed simultaneously. Find the probability of getting

i) exactly one head

ii) at least one tail

iii) no tail

iv) at most one head

Answer 1

When two coins are tossed the results are $(HH,HT,TH,TT)$

Total no. of outcomes $=4$

$1)$ Exactly one head $=$ only two cases are $(HT,TH)$

$=\frac{2}{4}=\frac{1}{2}$

$2)$ At least one tail $=$ There are three cases $(HT,TH,TT)$

$=\frac{3}{4}$

$3)$ No. tail $=$ only one case (HH) $=\frac{1}{4}$

$4)$ Atmost one head $=$three cases $(HT,TH,TT)$

$=\frac{3}{4}$.