Question

Two coins are tossed simultaneously. What is the probability of getting at most one head?
(a) $\frac{1}{4}$
(b) $\frac{1}{2}$
(c) $\frac{2}{3}$
(d) $\frac{3}{4}$

Answer 1

(d) $\frac{3}{4}$

Explanation:
When two coins are tossed simultaneously, the possible outcomes are HH, HT, TH and TT.
Total number of possible outcomes = 4

Let E be the event of getting at most one head.

Then, the favourable outcomes are HT, TH and TT.​
​Number of favourable outcomes = 3

∴ P(getting at most 1head) = ​$\frac{\mathrm{Number}\mathrm{of}\mathrm{favo}\text{u}\mathrm{rable}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{possible}\mathrm{outcomes}}=\frac{3}{4}$