Two column namely face to face and back to back arrangement of same channel section are shown below. For most optimum utilization of the section the spacing requirement is _______.

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Solution

$I_{x x c o m b i n a t i o n}$ = ${2 I}_{x x o n e}$
$I_{y y c o m b i n a t i o n}$ = $2 [I_{y y, o n e} + A_{o n e} {(C_{y y} + \frac{S}{2})}^{2}]$

$I_{x x^{'} c o m b i n a t i o n}$ = ${2 I}_{x x o n e}$
$I_{y y^{'} c o m b i n a t i o n}$ = $2 [I_{y y, o n e} + A_{o n e} {((b - C_{y y}) + \frac{S}{2})}^{2}]$

but
$b - C_{y y} > C_{y y}$
$\Rightarrow$ Spacing (s) is lesser in face to face arrangement.

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Cross - sectional area (A) = 5366 m m^{2}

C_{y y} = 24.4 m m

I_{z z} = 10008 c m^{4}

I_{y y} = 430.6 c m^{4}

= 4546 m m^{2}

r_{x x} = 118.1 m m, r_{y y} = 20.18 m m a n d C_{y y} = 23.6 m m

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