Two complementary angles differ by 10°. The larger angle is

(a) 60°
(b) 50°
(c) 64°
(d) 54°

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Solution

$(b) 50 ° Let the angle be x ° . Then, complementary of x = 90 ° - x ° According to the question, we have : x - 90 - x = 10 \Rightarrow 2 x = 90 + 10 \Rightarrow 2 x = 100 \Rightarrow x = 50 So, the larger angle is 50 ° .$

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Question 18

The difference fo two complementary angles is $30^{\circ} .$ Then the angles are
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Two complementary angles differ by 10°. The larger angle is (a) 60° (b) 50° (c) 64° (d) 54°

(b) 50°Let the angle be x°.Then, complementary of x=90°-x°According to the question, we have:x-90-x=10⇒2x=90+10⇒2x=100⇒x=50So, the larger angle is 50°.

Two complementary angles differ by 10°. The larger angle is

(a) 60°
(b) 50°
(c) 64°
(d) 54°

$(b) 50 ° Let the angle be x ° . Then, complementary of x = 90 ° - x ° According to the question, we have : x - 90 - x = 10 \Rightarrow 2 x = 90 + 10 \Rightarrow 2 x = 100 \Rightarrow x = 50 So, the larger angle is 50 ° .$