Question 1) two complementary angles differ by 20. Find the angles.
Question 2) 150 has been divided into 2 parts such that twice the first part is equal to the second part. Find the parts.
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Solution
(1) Sum of two complementary angles= 90° let one of the complementary angles be x and second angle be x-20(since difference is 20) then a/q x+ x-20=90 =2x = 90+20 = x= 110/2 ∴x= 55 so measure of one angle is 55° and the second angle is 55-20= 35° and 55+35= 90°
(2)
let the 1st part be x
given second part is twice the first part i.e = 2x
as sum of first and second part is 150 x+2x=150 3x=150 x=150/3 x=50 so first part is 50 second part=2x=2*50=100