Two complex numbers are represented by ordered pairs $z_{1} : (6, 4) & z_{2} : (4, - 5)$ , which of the following is real part of $z_{1} + z_{2}$ ?

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $10$
z1 : (6, 4) is written as z1 = 6 + 4i
z2 : (4, -5) is written as z2 = 4 - 5i
$∴ z 1 + z 2 = 10 - i ∴ R e (z 1 + z 2) = 10$

Suggest Corrections

Similar questions

z_{1} : (6, 4) & z_{2} : (4, - 5)

z_{1} + z_{2}

z_{1} : (2, 4) & z_{2} : (- 4, 5)

z_{1} \times z_{2} =

z_{1} : (2, 4) & z_{2} : (- 4, 5)

z_{1} \times z_{2} =

z_{1} : (3, 4) & z_{2} : (4, 5)

z_{1} + z_{2}

z_{1} : (a, 0) & z_{2} : (c, d)

z_{1} \times z_{2} =

Join BYJU'S Learning Program