Two concentric circles are intersected by a line L at A, B, C and D. Then
AB = CD
Let OP be perpendicular to line L.
Perpendicular from the centre of a circle to the chord bisects the chord.
BP = PC (i) (OP is perpendicular to chord BC)
AP =PD (ii) (OP is perpendicular to chord AD)
Subtracting (i) from (ii) you get
AP – BP = PD – PC
Or AB = CD