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Question

Two concentric circles with centre C have radii r1 and r2 such that (r2r1)>0. CA and CB are the common lined radii of the circles. If tangent at A is drawn to meet the bigger circle in the point D. Then the length BD is given by

A
2r1(r2r1)
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B
2r2(r2r1)
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C
2r1(r2+r1)
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D
2r2(r2+r1)
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Solution

The correct option is B 2r2(r2r1)
AB=r2r1
From DCA,DAC=90o
DA=r22r21
From DAB,DAB=90o
BD=r22r21+(r2r1)2
BD=r22r21+r22+r212r1r2=2r2(r2r1)
941267_923543_ans_395e860aca7d4f9598ce44908caebe1a.png

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