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Question

Two concentric circular coils, each having 10 turns with radii 0.2m and 0.4m carry currents 0.2A and 0.3A respectively in opposite direction. Magnetic field at the centre is

A
(2/3)μ0
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B
(5/4)μ0
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C
(1/4)μ0
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D
(1/6)μ0
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Solution

The correct option is A (5/4)μ0
The magnetic field at the centre of a circular loop carrying current is given by
B=nμ0I2R, where n is the number of turns.

Thus, the magnetic field due to first coil is B1=10×μ0×0.22×0.2=5μ0
Magnetic field due to second coil is B2=10×μ0×0.32×0.4=3.75μ0

Net magnetic field is B=B1B2=(53.75)μ0=(5/4)μ0

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