Given: The radius of the coil X is 16 cm, the radius of coil Y 10 cm, the numbers of turns on coil X are 20, the numbers of turns on coil Y are 25, the current in coil X is 16 A and the current in coil Y is 18 A.
The magnetic field due to coil Xat their centre is given as,
B 1 = μ 0 N 1 I 1 2 r 1
Where, the radius of the coil X is r 1 , the numbers of turns on coil X are n 1 , the current in coil X is I 1 and the permeability of free space is μ 0 .
By substituting the given values in the above formula, we get
B 1 = 4π× 10 −7 ×20×16 2×0.16 =4π× 10 −4 T
The magnetic field due to coil Yat their centre is given as,
B 2 = μ 0 N 2 I 2 2 r 2
Where, the radius of the coil Y is r 2 , the numbers of turns on coil Y are n 2 and the current in coil Y is I 2 .
By substituting the given values in the above formula, we get
B 2 = 4π× 10 −7 ×25×18 2×0.1 =9π× 10 −4 T
The net magnetic field is given as,
B= B 2 − B 1
By substituting the given values in the above formula, we get
B=9π× 10 −4 −4π× 10 −4 =5π× 10 −4 =1.57× 10 −4 T
Thus, the net magnetic field due to the coils at their centre is 1.57× 10 −4 Ttowards west direction.