Two condensers, each of capacitance 1μF, are connected in parallel. These are charged by a DC source of 200 volt. The total energy of their charges in joule will be
A
0.06
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B
0.04
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C
0.02
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D
0.01
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Solution
The correct option is D 0.04 As two capacitors are connected in parallel, the equivalent capacitance of the system is Ceq=C+C=2μF Energy stored in this system is U=12CeqV2=12×2×10−6×(200)2=0.04J