Two condensers each of capacitance $2 μ F$ are connected in parallel and this combination is connected in series with a $12 μ F$ capacitor. The resultant capacity of the system will be:

16 μ f

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13 μ f

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6 μ f

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3 μ f

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Solution

The correct option is D $3 μ f$
When two capacitors of capacitance $2 μ F$ are in parallel , the equivalent capacitance is
$C_{e q} = 2 + 2 = 4 μ F$ . Now it is connected to $12 μ F$ in series . So the capacitance of system is $C_{s y s} = \frac{4 \times 12}{4 + 12} = 3 μ F$

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Two condensers each of capacitance 2μF are connected in parallel and this combination is connected in series with a 12μF capacitor. The resultant capacity of the system will be:

The correct option is D 3μfWhen two capacitors of capacitance 2μF are in parallel , the equivalent capacitance isCeq=2+2=4μF. Now it is connected to 12μF in series . So the capacitance of system is Csys=4×124+12=3μF

Two condensers each of capacitance $2 μ F$ are connected in parallel and this combination is connected in series with a $12 μ F$ capacitor. The resultant capacity of the system will be:

The correct option is D $3 μ f$
When two capacitors of capacitance $2 μ F$ are in parallel , the equivalent capacitance is
$C_{e q} = 2 + 2 = 4 μ F$ . Now it is connected to $12 μ F$ in series . So the capacitance of system is $C_{s y s} = \frac{4 \times 12}{4 + 12} = 3 μ F$