Question

Two condensers of capacity $4\mu F$ and $6\mu F$ are connected in series. A potential difference of 500 volt is applied between the outer plates of the compound capacitor. The numerical value of charge on each condenser will be :

• A. $1200\mu C$
• B. $1200C$
• C. $6000\mu C$
• D. $6000C$

Answer 1

Answer: (A)

$1200\mu C$

The equivalent capacitance is $C_{eq}=\frac{4\times 6}{4+6}=\frac{24}{10}\mu C$
and $Q_{eq}=C_{eq}V=\frac{24}{10}\times 500=1200\mu C$
As the capacitors are in series so the charge on each capacitors is equal to the equivalent charge. i.e $Q_4=Q_6=Q_{eq}=1200\mu C$