Question

Two cones $A$ and $B$ have their base $r$ in the ratio of $4:3$ and their heights in the ratio $3:4$ of ratio of volume of cone $A$ to that of cone.

• A. $4:3$
• B. $3:4$
• C. $2:3$
• D. $1:2$

Answer 1

The correct option is A $4:3$

$\frac{VolumeofA}{VolumeofB}=\frac{\frac{1}{3}\pi {\left(4r\right)}^2.3h}{\frac{1}{3}\pi {\left(3r\right)}^2.4h}=\frac{4}{3}$