Two consecutive angles of a parallelogram measure $3 x + 42$ and $9 x - 18$ . What is the value of x ?

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Solution

The correct option is C $13$
$3 x + 42$ and $9 x - 18$ are consecutive angles of a parallelogram.
Thus,
$3 x + 42 + 9 x - 18 = 180$
$12 x = 156$
$x = 13$

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Two consecutive angles of a parallelogram measure 3x+42 and 9x−18. What is the value of x ?

The correct option is C 133x+42 and 9x−18 are consecutive angles of a parallelogram.Thus,3x+42+9x−18=18012x=156x=13

Two consecutive angles of a parallelogram measure $3 x + 42$ and $9 x - 18$ . What is the value of x ?

The correct option is C $13$
$3 x + 42$ and $9 x - 18$ are consecutive angles of a parallelogram.
Thus,
$3 x + 42 + 9 x - 18 = 180$
$12 x = 156$
$x = 13$