Question

Two consecutive odd numbers are such that when the smaller number is subtracted from three times the bigger number, the result is $56$. The bigger number is:

• A. $29$
• B. $31$
• C. $25$
• D. $27$

Answer 1

The correct option is D $27$

Let the two consecutive odd numbers be $x$ and $x+1$.
As per given question, the following equation can be formed.
$3(x+1)-x=56$
$\Rightarrow 3x+3-x=56$
$\Rightarrow 2x=53$
$\Rightarrow x=26$
Therefore, the bigger number is $(x+1)$ that is $26+1=27$.