Question

Two containers (I) and (II) with volume $2$ litre and $3$ litre are separated through a stopcock as shown in the diagram. Container (I) contains three gases $A,B,$ and $C$ with mole ratio $1:2:3$ and total pressure $30$ atm. If stopcock is opened then calculate the pressure of gas $C$ in a container (II). (Assume temperature remains constant)

Answer 1

$\text{According to Boyle's law, P}{}_1\text{V}{}_{initial}\text{= P}{}_2\text{V}{}_{final}\Rightarrow \left(30\right)\left(2litres\right)=P_2\left(5litre\right)\Rightarrow P_2=12atm\Rightarrow \text{Total Pressure = 12 atm}\text{Partial Pressure of C =}\frac{2}{1+2+3}\times 12=4atm$