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Question

Two copper spheres of radii 6cm and 12cm respectively are suspended in an evacuated enclosure. Each of them are at a temperature 150C above the surroundings. The ratio of their rate of loss of heat is ___________.

A
2:1
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B
1:4
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C
1:8
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D
8:1
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Solution

The correct option is C 1:4
According to the Stefan-Boltzmann law, the rate of loss of heat from a hot body is given as
P=σA(T4T4c)
=σ4πr2(T4T4c)
Hence P1P2=r21r22
=62122
=14

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