Two copper wires having the length in ratio $4 : 1$ and their radii ratio as $1 : 4$ are stretched by the same force. Then the ratio of the longitudinal strain in the two will be

1 : 16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 : 64

No worries! We‘ve got your back. Try BYJU‘S free classes today!

64 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $16 : 1$
Stress $\propto$ Strain $\propto \frac{F}{A}$
Ratio of strain $= \frac{A_{2}}{A_{1}} = {(\frac{r_{2}}{r_{1}})}^{2} = {(\frac{4}{1})}^{2} = (\frac{16}{1})$

Suggest Corrections

Similar questions

Q. Two wires of copper having the length in the ratio 4 : 1 and their radii ratio as 1 : 4 are stretched by the same force. The ratio of longitudinal strain in the two will be:

Q. Two wires of the same material have lengths in the ratio 1 : 2 and their radii are in the ratio 1 :

\sqrt{2}

. If they are stretched by applying equal forces, the increase in their lengths will be in the ratio

Q. Two wires of same material and radius have their lengths in ratio

1 : 2

. If these wires are stretched by the same force, the strain produced in the two wires will be in the ratio

Two wires of the same material have diameter in the ratio 2:1 and length in the ratio 1:2. If they are stretched by the same force, their elongation will be in the ratio

Q. Two wires of different material and radius have their length in ratio of

1 : 2.

if these were stretched by the same force

,

the strain produced will be in the ratio

.

Join BYJU'S Learning Program

Two copper wires having the length in ratio 4:1 and their radii ratio as 1:4 are stretched by the same force. Then the ratio of the longitudinal strain in the two will be

The correct option is B 16:1Stress∝ Strain ∝FARatio of strain =A2A1=(r2r1)2=(41)2=(161)

Two copper wires having the length in ratio $4 : 1$ and their radii ratio as $1 : 4$ are stretched by the same force. Then the ratio of the longitudinal strain in the two will be

The correct option is B $16 : 1$
Stress $\propto$ Strain $\propto \frac{F}{A}$
Ratio of strain $= \frac{A_{2}}{A_{1}} = {(\frac{r_{2}}{r_{1}})}^{2} = {(\frac{4}{1})}^{2} = (\frac{16}{1})$