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# Question 6 Two crossroads, each of width 10 m, cut at right angle through the center of a rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area of the roads. Also, find the area of the park excluding crossroads. Give the answer in hectares.

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Solution

## Here PQ = 10 m and PS = 300 m, EH = 10 m and EF = 700 m and KL=10 and KN = 10 m Area of roads = Area of PQRS + Area of EFGH – Area of KLMN [ ∵ KLMN is taken twice which is to be subtracted ] =PS×PQ+EF×EH−KL×KN =(300×10)+(700×10)−(10×10) =3000+7000−100 =9,900m2 Area of road in hectares, 1m2=110000 hectares ∴ 9,900m2=990010000=0.99 hectares Now, Area of park excluding cross roads = Area of park - Area of roads =(AB×AD)−9,900 =(700×300)−9,900 =2,10,000−9,900 =200100 m2 =2001001000 hectares=20.01 hectares  Suggest Corrections  3      Similar questions
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