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Question 6

Two crossroads, each of width 10 m, cut at right angle through the center of a rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area of the roads. Also, find the area of the park excluding crossroads. Give the answer in hectares.


Solution


Here PQ = 10 m and PS = 300 m, EH = 10 m and EF = 700 m and KL=10 and KN = 10 m
Area of roads = Area of PQRS + Area of EFGH – Area of KLMN
[   KLMN is taken twice which is to be subtracted ]
=PS×PQ+EF×EHKL×KN
=(300×10)+(700×10)(10×10)
=3000+7000100
=9,900m2
Area of road in hectares, 1m2=110000 hectares
9,900m2=990010000=0.99 hectares
Now, Area of park excluding cross roads
= Area of park - Area of roads
=(AB×AD)9,900
=(700×300)9,900
=2,10,0009,900
=200100 m2
=2001001000 hectares=20.01 hectares
 

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