Two cubes each of side $12 c m,$ are joined end to end .the surface area of the resulting cuboid is :

{1240 c m}^{2}

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{1440 c m}^{2}

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{2250 c m}^{2}

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{4252 c m}^{2}

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Solution

The correct option is B ${1440 c m}^{2}$
$l e n g t h o f t h e r e s u l t i n g c u b o i d$
$12 + 12$
$= 24 c m$
$B r e a d t h a n d h e i g h t r e m a i n i n g t h e s a m e$
$s u r f a c e a r e a = 2 (l b + b h + l h)$
$= 2 (24 \times 12 + 12 \times 12 + 24 \times 12)$
$= 1440 c m^{2}$

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