Question

Two cubes each of volume 125 $c{m}^3$ are joined end to end to form a solid. Find the surface area of the resulting cuboid.

Answer 1

Volume of each cube = 125 $c{m}^3$

So, edge of each cube = 5 cm

For new cuboid formed, l = 5+5 = 10 cm

b = 5 cm

h = 5 cm

Therefore, surface area of the resulting cuboid = 2 (lb + bh + lh)

= 2 (10 × 5 + 5 × 5 + 10 × 5) $c{m}^2$

= 250$c{m}^2$