Question

Two cubes each of volume 216 $c{m}^3$ are joined to form a cuboid as shown in the figure.
Find the T.S.A of the resulting cuboid.

Answer 1

Let the side of each cube be a. Then $a^3=216$
$\therefore a{=}^3\sqrt{216}=6cm$
Now the two cubes of side 6 cm are joined to form a cuboid. So,
$\therefore l=6+6=12cm,b=6cm,h=6cm$
$\therefore T.S.A=2(lb+bh+lh)$
$=2\left[\right(12\times 6)+(6\times 6)+(12\times 6\left)\right]$
$=2[72+36+72]$
$=2\times 180=360c{m}^2$