Question

Two cubes each of volume 64 $c{m}^3$ are joined end to end. Find the surface area of the resulting cuboid.

Answer 1

The volume of cube $64c{m}^3$

Side of cube $\sqrt[3]{364}=4cm$

Length of resulting cuboid $4+4=8$

Surface area

$=2(lb+hl+bh)$

$=2\left(4\right(4)+4(8)+8(4\left)\right)=2(16+32+32)=2\left(80\right)=160c{m}^2$