Two cubes with sides $6 c m$ are placed one above the other, forming a cuboid. Find the total surface area of the cuboid thus formed

320

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360

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380

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440

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Solution

The correct option is B: $360 c m^{2}$

Side of the cube, $a = 6 c m$
Therefore, Length of the cuboid, $l = 6 c m$
Breadth of the cuboid, $b = 6 c m$
And height, $h = 6 + 6 = 12 c m$
Total surface area $= 2 (l b + l h + b h)$
$= 2 (6 \times 6 + 6 \times 12 + 6 \times 12)$
$= 360 c m^{2}$

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