i) Possibility of visiting the shop on same day ={(tue,tue),(wed,wed),(thurs,thurs),(fri,fri),(sat,sat)}
Total outcomes is 5×5=25
P(on the same day) =525=15
ii) Possibility of visiting the shop on consecutive days ={(tue,wed),(wed,thurs),(thurs,fri),(fri,sat),(thurs,wed),(fri,thurs),(sat,fri),(wed,tue)}
Total outcomes is 25.
P(on consecutive days) =825
iii) Possibility of visiting the shop on different days ={tue,wed,thurs,fri,sat}
P(on different days) =1− P(on same day) =1−15=45