Two cyclist start from the junction of two perpendicular roads, their velocities being 3v metres/minute and 4v metres/minute . The rate at which the two cyclists are separating is
A
72v m/min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5v m/min
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
v m/min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B5v m/min The cyclist will be separating along the vector sum of the perpendicular velocity vectors of the two cyclists, since their speeds are constant. Hence they will be separating at the rate √(3v)2+(4v)2. =5vm/min