You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Thermal Expansion

Two cylinders...

Question

Two cylinders of same cross section area and length L but made of two material of densities $d_{1}$ and $d_{2}$ are connected together to form a cylinder of length 2L. The combination floats in a liquid of density d with a length $\frac{L}{2}$ above the surface of the liquid. If $d_{1} > d_{2}$ then

$d_{1} > \frac{3}{4} d$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{d}{2} > d_{1}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{d}{4} > d_{1}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$d < d_{1}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$d_{1} > \frac{3}{4} d$

$U = m g \Rightarrow d A \frac{3 L}{2} g = d_{1} A L g + d_{2} A L g$

Suggest Corrections

Similar questions

Q. Two cylinders of same cross-section and length

L

but made of two different materials of densities

d_{1}

and

d_{2}

are cemented together to form a cylinder of length

2 L

. The combination floats in a liquid of density

d

with a length

\frac{L}{2}

above the surface of the liquid. If

d_{1} < d_{2}

then

Q. Two cylinders of same cross-section and length

L

but made of two materials of densities

d_{1}

and

d_{2}

are connected together to a form a cylinder of length

2 L

. The combination floats in a liquid of density

d

with a length

\frac{L}{2}

above the surface of the liquid. If

d_{1} < d_{2}

, then

Q. Two cylinders of same cross-section and length

L

but made of two different materials of densities

d_{1}

and

d_{2}

are cemented together to form a cylinder of length

2 L

. The combination floats in a liquid of density

d

with a length

\frac{L}{2}

above the surface of the liquid. If

d_{1} < d_{2}

then

Q. In the arrangement as shown, A and B are two cylinders each of length L and density

d_{1}

and

d_{2} (d_{1} < d_{2})

, respectively. They are joined together and submerged in the liquid of density d with length L/2 of A outside the liquid. If the difference in densities of two cylinders is equal to density of the liquid, find

d_{1}

A body of density d and volume V floats with volume $V_{1}$ of it immersed in a liquid of density $d_{1}$ and rest of the volume $V_{2}$ immersed in another liquid of density $d_{2}$ (< $d_{1}$ ) then $V_{1}$ is

Join BYJU'S Learning Program

Two cylinders of same cross section area and length L but made of two material of densities d1 and d2 are connected together to form a cylinder of length 2L. The combination floats in a liquid of density d with a length L2 above the surface of the liquid. If d1>d2 then

The correct option is A d1>34d U=mg⇒dA3L2g=d1ALg+d2ALg

The correct option is A
$d_{1} > \frac{3}{4} d$

$U = m g \Rightarrow d A \frac{3 L}{2} g = d_{1} A L g + d_{2} A L g$