The correct options are
A The pressure acting on the piston A = 3,125 kgf m−2
B The pressure acting on the piston B = 3,125 kgf m−2
D The thrust acting on the piston B = 125 kgf
Given:
The area of cross section of the piston A, A1=8 cm2
The area of cross section of the piston B, A2=400 cm2
The mass put on the piston A = 2.5 kg⟹ Force acting on the piston A, F1≈2.5 kgf (∵1 kg≈1 kgf)
The pressure acting on the piston A, P1=F1A1=2.58=0.3125 kgf cm−2⟹P1=3,125 kgf m−2
According to Pascal's law, this pressure will be transmitted equally and undiminished in all directions in the liquid, i.e. the pressure acting on the piston B would also be equal to 3,125 kgf m−2.
⟹ Thrust acting on the piston B = 3125×400×10−4=125 kgf